Determine the power loss in watts for two conductors with a total resistance of 0.40 ohms carrying 16A.

Study for the Electrical Theory Test. Study with flashcards and multiple-choice questions, each question has hints and explanations. Get ready for your exam!

To find the power loss in watts for the conductors, you can use the formula for electrical power loss, which is given by:

[ P = I^2 \times R ]

where ( P ) is the power loss in watts, ( I ) is the current in amperes, and ( R ) is the resistance in ohms.

In this scenario, the total resistance of the conductors is 0.40 ohms, and the current being carried is 16A. Substituting these values into the formula gives:

[ P = 16^2 \times 0.40 ]

[ P = 256 \times 0.40 ]

[ P = 102.40 \text{ W} ]

Therefore, the power loss for the two conductors is 102.40 watts. This calculation highlights how power loss in conductors is directly related to the square of the current and the resistance. Increasing either the current or resistance would result in a higher power loss, demonstrating the importance of minimizing resistance in electrical systems for efficiency.

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